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(5-1)x^2-2(5+1)x+5+4=0
We add all the numbers together, and all the variables
4x^2-26x+5+4=0
We add all the numbers together, and all the variables
4x^2-26x+9=0
a = 4; b = -26; c = +9;
Δ = b2-4ac
Δ = -262-4·4·9
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{133}}{2*4}=\frac{26-2\sqrt{133}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{133}}{2*4}=\frac{26+2\sqrt{133}}{8} $
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